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The ratio of intensities between two coherent sound sources is `4:1` the difference of loudness in decibels between maximum and minimum intensities, when they interfere in space, isA. `10 log 2`B. `20 log 3`C. `10 log 3`D. `20 log 2` |
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Answer» Correct Answer - B Given `(I_1)/(I_2)=(4)/(1)` We know `Ipropa^2` `:. (a_1^2)/(a_2^2)=(I_1)/(I_2)=(4)/(1)` or `:. (a_1)/(a_2)=(2)/(1)` `(I_(max))/(I_(min))=((a_1+a_2)^2)/((a_1-a_2)^2)=((2+1)/(2-1))^2` `=((3)/(1))^2=(9)/(1)` Therefore, difference of loudness is given by `L_1-L_2=10log_(10).(I_(max))/(I_(min))=10log(9)` `=10log3^2=20log3` |
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