The ratio of the diameters of a torus and mesh of dimensions 8 x sqrt(

1.	The ratio of the diameters of a torus and mesh of dimensions 8 x sqrt(n) x (1/8 x sqrt(n)) is
Answer» "The ratio of the DIAMETER of the torus and MESH of the dimension diameter of the torus : mesh of the dimension 8 square root n : 1/8 square root n Square root will cancel out square root 8 : 1/8 A DIVIDED by B/C = A * C divided by B 8 * 8 : 1 64 : 1 "

The ratio of the diameters of a torus and mesh of dimensions 8 x sqrt(n) x (1/8 x sqrt(n)) is

Answer»

"The ratio of the DIAMETER of the torus and MESH of the dimension

diameter of the torus : mesh of the dimension

8 square root n : 1/8 square root n

Square root will cancel out square root

8 : 1/8

A DIVIDED by B/C = A * C divided by B

8 * 8 : 1

64 : 1