The ratio of times taken by freely falling body to cover first metre s

1.	The ratio of times taken by freely falling body to cover first metre second metre is
Answer» Answer: 1 : (√2 - 1) Explanation: Time TAKEN for FIRST 1 m t = √(2H/g) = √(2 × 1/g) = √(2/g) Time taken for first 2 m T = √(2 × 2/g) = √(4/g) Time taken for SECOND 1 m is then T - t = √(4/g) - √(2/g) Ratio = √(2/g) / [√(4/g) - √(2/g)] = √2 / (√4 - √2) = √2 / (√2(√2 - 1)) = 1 : (√2 - 1)

The ratio of times taken by freely falling body to cover first metre second metre is

Answer»

Answer:

1 : (√2 - 1)

Explanation:

Time TAKEN for FIRST 1 m

t = √(2H/g)

= √(2 × 1/g)

= √(2/g)

Time taken for first 2 m

T = √(2 × 2/g)

= √(4/g)

Time taken for SECOND 1 m is then

T - t = √(4/g) - √(2/g)

Ratio = √(2/g) / [√(4/g) - √(2/g)]

= √2 / (√4 - √2)

= √2 / (√2(√2 - 1))

= 1 : (√2 - 1)

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The ratio of times taken by freely falling body to cover first metre second metre is​

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The ratio of times taken by freely falling body to cover first metre second metre is