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The reaction,`2NO+2H_(2)rarr N_(2)+2H_(2)O` has been assigned to follow the following mechanism I. `NO+NO hArr N_(2)O_(2)" "` (fast) II.`N_(2)O_(2)+H_(2) rarr N_(2)O+H_(2)O " "` (slow) III. `N_(2)O +H_(2) rarr N_(2)+H_(2)O " "` (fast) The rate constant of step II is `1.2 xx 10^(-4) "mole"^(-1)L"min"^(-1)` while equilibrium constant of step I is `1.4 xx 10^(-2)` . What is the rate of reaction when concentration of NO and `H_(2)` each is 0.5 mole `L^(-1)`?A. `2.1 xx 10^(-7)` mol`L^(-1) "min"^(-1)`B. `3.2 xx 10^(-6)` mol`L^(-1) "min"^(-1)`C. `3.5 xx 10^(-4)` mol`L^(-1) "min"^(-1)`D. None of above

Answer» Correct Answer - A


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