InterviewSolution
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InterviewSolution
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The reaction `3A to 2B+C` is carried in a closed vessel. The rate of disappearance of `A[(-d[A])/(dt)]` is 0.01 `molL^(-1)s^(-1)`. Calculate `(d[B])/(dt)` and `(d[C])/(dt)`. |
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Answer» For the reaction, `3A to 2B + C` Rate = Rate = `1/3 xx (-d[A])/(dt) = 1/2 xx(d[B])/(dt)=(d[C])/(dt)` `(d[B])/(dt) = 2/3 xx (d[A])/(dt) = 2/3 xx 0.01 = 0.0067 mol L^(-1)s^(-1)` `(d[C])/(dt) = 1/3 xx (d[A])/(dt) = 1/3 xx 0.01 = 0.0033 mol L^(-1)s^(-1)` |
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