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The reaction `Ararr B` follows first order kinetics. The time taken for `0.8 mol` of `A` to profuce `0.6 mol` of `B` is `1 hr`. What is the time taken for the converison of `9.0 mol` of `A` to Product `0.675 mol` of `B` ?A. `1 hr`B. `0.5 hr`C. `0.25 hr`D. `2 hr` |
Answer» Correct Answer - A Time for the converison of `0.8 mol` of `A` to `0.6 mol` of `B = (0.6)/(0.8) = 0.75 =t_(75%)` ismilarly, time for the converison of `0.9 mol` of `A` to `0.675 mol` of `B = (0.675)/(0.9) = 0.75 = t_(75%)` Hence, `t_(75%)` in both case `= 1 hr` |
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