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The reaction `N_(2)O_(5)` (in `C Cl_(4)` solution ) `to 2 NO_(2)` (solution) `+ (1)/(2) O_(2)` (gas ) is of first order in `N_(2)O_(5)` with rate constant `6.2 xx 10^(-1) s^(-1)` . What is the value of rate of reaction when `[N_(2)O_(5)] = 1.25 "mole" l^(-1)`A. `7.75 xx 10^(-1) "mole" l^(-1) s^(-1)`B. `6.35 xx 10^(-3) "mole" l^(-1) s^(-1)`C. `5.15 xx 10^(-5) "mole" l^(-1) s^(-1)`D. `3.85 xx 10^(-1) "mole" l^(-1) s^(-1)` |
Answer» Correct Answer - a Rate = `k (N_(2)O_(5)) = 6.2 xx 10^(-1) xx 1.25` = `7.75 xx 10^(-1)` mol `l^(-1) s^(-1)`. |
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