InterviewSolution
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InterviewSolution
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The rear side of a truck is open and a box of mass `20kg` is placed on the truck `4m` away from the open end `mu = 0.15` and `g = 10m//s^(2)` The truck starts from rest with an acceleration of `2m//s^(2)` on a straight road The box will fall off the truck when it is at a distance from the starting point equal to .A. `14m`B. `8m`C. `16m`D. `4m` |
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Answer» Correct Answer - c Max acc. Of the block ` = mu g = 0.5 xx 10` `=1.5m//s^(2)` Acc. Of truck `=2m//s^(2)` `:.` Relative acc. Of box w.r.t truck `a_(r) = 1.5` `-2.0 = -0.5m//s^(2)` (backwards) It will fall off the truck in a time `t = sqrt((2l)/(a_(r))) =sqrt(((2xx4))/(0.5)) = 4s` Displacement of truck during this time `s = (1)/(2)at^(2) = (1)/(2)xx2xx4^(2) =16m` . |
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