InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The refracting angle of a glass prism is `30^@.` A ray is incident onto one of the faces perpendicular to it. Find the angle `delta` between the incident ray and the ray that leaves the prism. The refractive index of glass is `mu=1.5.` |
|
Answer» Correct Answer - A::D Given , `A=30^@, mu=1.5` and `i_1=0^@` Since, `i_0^@,` therefore, `r_1` is also equal to `0^@.` Further, since, `r_1+r_2=A` `:. r_2=A=30^@` Using, `mu=sin i_2/sin r_2` we have, `1.5=sin i_2/sin30^@` or `sin i_2=1.5sin 30^@` `=1.5xx1/2=0.75` `:. i_2=sin^-1(0.75)=48.6^@` Now, the deviation, `delta=(i_1+i_2)-A` `=(0+48.6)-30` or `delta=18.6^@` |
|