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The relation `3t=sqrt(3x)+6` describe the displacement of a particle in one direction where x is in metres and t in sec. The displacement, when velocity is zero isA. 24 mB. 12 mC. 5 mD. zero |
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Answer» Correct Answer - D `3t=sqrt(3x)+6` `x=3(t-2)^(2)` `v=(dx)/(dt)=6(t-2)` When `v=0impliest=2 s` Atv `t=2 s, x=0` |
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