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The relation between change in internal energy`(DeltaE)`change in enthalpy`(DeltaH)` and work done`(W)`is represented asA. 30.5 kJB. 33 kJC. `-28 kJ`D. `-30.5 kJ` |
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Answer» Correct Answer - D `DeltaG_(30) = Delta H_(30 + T. (d)/(dT) (Delta G)_(p)` |
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