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The remainder and the quotient of the binary division `(101110)_2 -: (110)_2` respectivelyA. `(111)_(2) and (100)_(2)`B. `(100)_(2) and (111)_(2)`C. `(101)_(2) and (101)_(2)`D. `(100)_(2) and (100)_(2)` |
Answer» Correct Answer - B `(101110)_(2)=1xx2^(5)+0xx2^(4)+1xx2^(3)+1xx2^(2)+1xx2^(1)+0xx2^(0)` `=32+0+8+4+2+0` `=(46)_(10)` Similarly, `(110)_(2)=1xx2^(2)+1xx2^(1)+0xx2^(0)` `=4+2` `=(6)_(10)` Quotient = 7 Remainder = 4 `(7)_(10)=(111)_(2) and (4)_(10)=(100)_(2)` |
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