1.

The resistances ci 0.05 M NaOH solution is 31.6 Ί and its cell constant is 0.357 cm-1Caicuiate its conductivity and molaz conductivity

Answer»

Conductivity= Conductance × cell constant= 1/Resistance × cell constant= 1/31.6 × 0.357 = 0.011 S

Molar conductivity= 1000× conductivity/ Molarity= 1000× 0.011/0.05 = 220S cm² mol^-1

thanx bhai



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