The rms speed of the molecules of a gas in a vessel is 400ms^-1.If hal

1.	The rms speed of the molecules of a gas in a vessel is 400ms^-1.If half of the gas leaks out at constant temperature ,the rms speed of the remaining molecules will bea.800ms^-1b.400.c.400ms^-1d.200ms^-1
Answer» Answer: EXPLANATION: Given, v rms =400m/s The RMS speed of the molecules will be v rms = M 3RT . . . . . .(1) where R= UNIVERSAL gas constant T= temperature M= molecular weight The RMS speed does not depend on the QUANTITY of the gas. For a given gas and the temperature, it remains constant. So, the RMS speed of the remaining molecules is 400m/s. The correct OPTION is C.

The rms speed of the molecules of a gas in a vessel is 400ms^-1.If half of the gas leaks out at constant temperature ,the rms speed of the remaining molecules will bea.800ms^-1b.400.c.400ms^-1d.200ms^-1

Answer»

Answer:

EXPLANATION:

Given,

rms

=400m/s

The RMS speed of the molecules will be

rms

3RT

. . . . . .(1)

where R= UNIVERSAL gas constant

T= temperature

M= molecular weight

The RMS speed does not depend on the QUANTITY of the gas. For a given gas and the temperature, it remains constant.

So, the RMS speed of the remaining molecules is 400m/s.

The correct OPTION is C.

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The rms speed of the molecules of a gas in a vessel is 400ms^-1.If half of the gas leaks out at constant temperature ,the rms speed of the remaining molecules will bea.800ms^-1b.400.c.400ms^-1d.200ms^-1​

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The rms speed of the molecules of a gas in a vessel is 400ms^-1.If half of the gas leaks out at constant temperature ,the rms speed of the remaining molecules will bea.800ms^-1b.400.c.400ms^-1d.200ms^-1