InterviewSolution
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The scalar `vecA.(vecB+vecC)xx(vecA+vecB+vecC)` equals (A) 0 (B) `[vecA vecB vecC]+[vecB vecC vecA]` (C) `[vecA vecB vecC]` (D) none of these |
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Answer» Correct Answer - a `vecA.(vecB + vecC) xx (vecA + vecB +vecC)` ` vecA . ([vecB xx vecA +vecB xx vecB + vecC + vecC xx vecA + vecC xx vecB +vecC xx vecC]` `= vecA.vecBxxvecA + vecA.vecBxxvecC+vecA.vecCxx vecA + vecA+ vecC xx vecB " " ( "using" veca xx veca =0)` `0+[vecA vecB vecC]+0+ [vecA vecC vecB]` `[vecA vecB vecC]-[vecA vecB vecC]` =0 |
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