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The scalars l and m such that `lveca + m vecb =vecc, " where " veca, vecb and vecc` are given vectors, are equal toA. `l= ((veccxxvecb).(vecaxxvecb))/((vecaxxvecb)^(2))`B. `l = ((vecc xx veca). (vecb xxveca))/((vecbxxveca))`C. `m = ((veccxx veca). (vecbxxveca))/((vecb xx veca)^(2))`D. `m = ((veccxx veca). (vecbxxveca))/((vecb xx veca))`

Answer» Correct Answer - a,c
Here, ` (l veca +mvecb) xx vecb =vecc xx vecb `
`or lveca xx vecb =vcec xx vecb`
`or l(veca xx vecb)^(2) = (vecc xx vecb) / (veca xx vecb)`
`or l= ((vecc xx vecb) . (veca xx vecb))/ ((veca xx vecb)^(2))`
similarly, `m = ((veccxxveca). (vecb xx veca))/((vecbxxveca)^(2))`


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