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    				| 1. | The second and fifth term of GP are 3 and 81/8 respectively. Find the GP | 
| Answer» Given T2 = ar = 3, T5 = ar4 = 81/8 T5/T2 = ar4/ar = r3 = (81/8)/3 = 27/8 ∴ r = 3√(33/23) = 3/2 If ar = 3 ⇒ a. 3/2 = 3 ⇒ a = 2 G.p is 2, 3, 9/2, ……. | |