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The second member of Lyman series inhydrogen spectrum has wavelength 5400 Aº.Find the wavelength of first member |
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Answer» Answer: Explanation: It is just an example do it yourself We have FORMULA , Here λ is wavelength , R is Rydberg constant i.e., RH = 109737 cm⁻¹ For Lyman SERIES ni = 1 and nf = 2, 3, 4, ....... ∞ But question is saying about 2nd line of Lyman series means , ni = 1 and nf = 3 So, 1/λ = 109737 cm⁻¹ × (1)² [ 1/1² - 1/3² ] [ for Hydrogen Spectra Z = 1 ] = 109737 × [1 - 1/9 ] = 109737 × 8/9 cm⁻¹ = 877896/9cm⁻¹ Now, λ = 9/877896 cm = 1.025 × 10⁻⁷ m = 102.5 nm |
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