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The second overtone of an open pipe A and closed pipe B have the same frequencies at a given temperature. Both pipes contain air. The ratio of fundamental frequency of a to the fundamental frequency of B isA. `3:5`B. `5:3`C. `5:6`D. `6:5` |
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Answer» Correct Answer - B Second overtone of open pipe `=(3V)/(2l_1)` Second overtone of closed pipe `=(5V)/(4l_2)` Since, ratio of frequency are same `(3V)/(2l_1)=(5V)/(4l_2)implies(l_1)/(l_2)=(4xx3)/(2xx5)=(6)/(5)` Now, the ratio of fundamental frequencies: `(f_1)/(f_2)=((V)/(2l_1))/((V)/(4l_2))implies(2l_2)/(l_1)=10:6=5:3` |
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