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The shadow of a tower at a time is three times as long as its shadow when the angle of elevation of the Sun is 60^(@). Find the angle of elevation of the Sum at the time of the longer shadow. |
Answer» `60^0` Let at Sun's elevation of `60^(@)`, its shadow be x. some Applications of Trigonometry Let `theta` be the ANGLE of elevation when its shadow is 3 times the FORMER i.e.,3x. ``In right `DeltaABC`, `tan60^(@)=h/xrArrsqrt3=h/xrArrh=xsqrt3...(1)` In right `DeltaABD`, `tantheta=h/(3x)` `=(xsqrt3)/(3x)"[from (1)]"` `=1/sqrt3=tan 30^(@)` `theta30^(@)` ![]() |
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