1.

The short-wavelength limit shifts by 26 pm when the operating voltage in an X-ray tube is increased to 1.5 times the original value. What was the original value of the operating voltage?

Answer» Correct Answer - A
`26 pm = 0.26 Å`
Now, 0.26 = (12475)/(V) - (12375)/(1.5 V).


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