1.

The sides of a parallelogram are `2hati +4hatj -5hatk and hati + 2hatj +3hatk `. The unit vector parallel to one of the diagonals isA. `(1)/(sqrt(69))(hati+2hatj-8hatk)`B. `(1)/(69)(hati+2hatj-8hatk)`C. `(1)/(sqrt(69))(-hati-2hatj+8hatk)`D. `(1)/(69)(-hati-2hatj+8hatk)`

Answer» Correct Answer - C
Since, `AB+BD=AD`
`BD=AD-AB`
`implies =(hati+2hatj+3hatk)-(2hati+4hatj-5hatk)`
`=-hati-2hatj+8hatk`
Hence, unit vector in the direction of BD is
`(-hati-2hatj+8hatk)/(|-hati-2hatj+8hatk|)=(-hati-2hatj+8hatk)/(sqrt(69))`.


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