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The sides of a parallelogram are `2hati +4hatj -5hatk and hati + 2hatj +3hatk `. The unit vector parallel to one of the diagonals isA. `(1)/(sqrt(69))(hati+2hatj-8hatk)`B. `(1)/(69)(hati+2hatj-8hatk)`C. `(1)/(sqrt(69))(-hati-2hatj+8hatk)`D. `(1)/(69)(-hati-2hatj+8hatk)` |
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Answer» Correct Answer - C Since, `AB+BD=AD` `BD=AD-AB` `implies =(hati+2hatj+3hatk)-(2hati+4hatj-5hatk)` `=-hati-2hatj+8hatk` Hence, unit vector in the direction of BD is `(-hati-2hatj+8hatk)/(|-hati-2hatj+8hatk|)=(-hati-2hatj+8hatk)/(sqrt(69))`. |
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