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The slope of a graph l n `[A_(t)]` versus t for a first order reaction is ` -2.5xx10^(-3) s^(-1)` . The rate constant for the reaction will beA. `5.76 xx10^(-3) S^(-1) `B. `1.086xx10^(-3)S^(-1) `C. `-2.5xx10^(-3) S^(-1)`D. `2.5 xx10^(-3) S^(-1)` |
Answer» Correct Answer - A Slope `=(-k)/(2.303)` `k=2.5xx10^(-3)xx2.303=5.76xx10^(-3)S^(-1)` |
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