InterviewSolution
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InterviewSolution
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The solubility of `BaSO_(4)` in water is `2.33xx10^(-3) g//litre`. Its solubility product will be (molecular weight of `BaSO_(4)=233`)A. `1xx10^(-5)`B. `1xx10^(-10)`C. `1xx10^(-15)`D. `1xx10^(-20)` |
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Answer» Correct Answer - B The solubility of `BaSO_(4)` in `g//litre` is given `2.33xx10` `:.` In mole//litre `n=(W)/(m.wt.)=(2.33xx10^(-3))/(233)` `=1xx10^(-5)` Because `BaSO_(4)` is a compound `K_(sp)=S^(2)=[1xx10^(-5)]^(2)=1xx10^(-10)` |
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