InterviewSolution
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The solution of dy/dx = ex-y is ______ (a) ey ex = c (b) y = log cex (c) y = log(ex + c) (d) ex+y = c |
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Answer» (c) y = log(ex + c) dy/dx = ex/ey \(\int\)ey dy = \(\int\)ex dx ⇒ ey = ex + c y = log(ex + c) |
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