1.

The solution of the DE x dy + ydx = 0 isA. x + y = CB. xy = CC. log (x + y) = CD. None of these

Answer»

Given xdy + ydx = 0

xdy = -ydx

\(- \frac{dy}{y} = \frac{dx}{x}\)

On integrating on both sides we get,

-log y = log x + c

log x + log y = c

log xy = c

xy = C

Conclusion: Therefore xy = c is the solution of xdy + ydx = 0



Discussion

No Comment Found