InterviewSolution
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The solution of the DE x dy + ydx = 0 isA. x + y = CB. xy = CC. log (x + y) = CD. None of these |
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Answer» Given xdy + ydx = 0 xdy = -ydx \(- \frac{dy}{y} = \frac{dx}{x}\) On integrating on both sides we get, -log y = log x + c log x + log y = c log xy = c xy = C Conclusion: Therefore xy = c is the solution of xdy + ydx = 0 |
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