1.

The solution of (y(1 + x–1) + sin y)dx + (x + loge x + x cos y)dy = 0 is(a)  (1 + y–1.sin y) + x-1.loge x = C(b)  y + sin y + xy logeX = C(c)  xy + y loge x + x sin y = C(d)   None of these

Answer»

Correct option (c) xy + y loge x + x sin y = C

Explanation:

ydx + y/x .dx + sin ydx + xdy + loge xdy + x cos ydy = 0

(ydx + xdy) + (y.dx/x + logexdy) +  (sin ydx + x cos ydy) = 0

= d(xy) + d(y loge x) + d(x sin y) = 0

xy + y loge x + x sin y = C



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