InterviewSolution
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The solution of (y(1 + x–1) + sin y)dx + (x + loge x + x cos y)dy = 0 is(a) (1 + y–1.sin y) + x-1.loge x = C(b) y + sin y + xy logeX = C(c) xy + y loge x + x sin y = C(d) None of these |
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Answer» Correct option (c) xy + y loge x + x sin y = C Explanation: ydx + y/x .dx + sin ydx + xdy + loge xdy + x cos ydy = 0 (ydx + xdy) + (y.dx/x + logexdy) + (sin ydx + x cos ydy) = 0 = d(xy) + d(y loge x) + d(x sin y) = 0 xy + y loge x + x sin y = C |
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