InterviewSolution
Saved Bookmarks
| 1. |
The sound intensity is `0.008W//m^( 2)` at a distance of 10 m from an isotropic point source of sound. The power of the source isA. 2.5 wB. 0.8 wC. 8 wD. 10 w |
|
Answer» Correct Answer - D `P/(4pir^(2))`=1 for an isotropic point sound source, `rArr F=L 4pir^(2)` `=(0.008w//m^(2))(4.pi.10^(2))` =10 watt |
|