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The spectral line for a given element in the light received from a distant star is shifted towards longer wavelength side by `0.032%`. Deduce the velocity of star in the line of sight.A. `9.6xx10^(4)ms^(-1)`B. `11.6xx10^(-4)ms^(-1)`C. `12.6xx10^(-4)ms^(-1)`D. None of these |
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Answer» Correct Answer - A Here, `(Deltalamda)/lamda=(0.032)/(100)` (position, as the shift is towards longer wavelength) Now, Doppler shift is given by, `Deltalamda=-v/clamda` `v=-(Deltalamda)/lamdac=-(0.032)/(100)xx3xx10^(8)=-9.6xx10^(4)ms^(-1)` The negative sign indicates that the star is receding. |
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