1.

The splash is heard after 2.05 s after the stone isdropped into a well of depth 19.6 m. The velocity ofsound is:(a) 342 ms(c) 392 ms(b) 372 ms"(d) 352 ms

Answer»

The time taken by the stone to reach the water level is, t= sqrt(2h/g), where h= Hight of the well, g= Acceleration due to gravity. So the time taken by the sound wave to travel the distance, which is the hight of the well is t’=(2.05-t). Now t=2 sec. Hence t’=0.5 sec.

Now the velocity of the sound wave will be, v= h/t’ =392 m/s.



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