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The standard enthaply for the reaction `H_(2)(g) + 1//2 O_(2)(g) to H_(2)O(l)` is - 285.76 kJ at 298 K. Calculate the value of `DeltaH` at 373 K .The molar heat capcities at constant pressure `(C_(P))` in the given temperature range of `H_(2)(g),O_(2)(g) and H_(2)O(l)` are respectively 38.83,16 and `75.312 JK^(-1) mol^(-1)`. |
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Answer» Correct Answer - `DeltaH_(373) (H_(2)O(l) )= - 284.11 kJ` `H_(2)- H_(1)= DeltaC_(p)(T_(2)-T_(1))` `H_(2) = - 284.11 kJ` |
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