1.

The standard free energy change `(DeltaG^(@))` is related to equilibrium constant (K) asA. `DeltaG^(@)=-2.303` RT log KB. `DeltaG^(@)=`RT log KC. `DeltaG^(@)=`2.303 RT log KD. `DeltaG^(@)=`-2.303 RT ln K

Answer» Correct Answer - A
Standard free energy change `(DeltaG^(@))`
`=-2.303 RT " log K"`.


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