Saved Bookmarks
| 1. |
The standard oxidation potential for the half-cell `NO_(2)^(-)(g)+H_(2)OtoNO_(3)^(-)(aq)+2H^(+)(aq)+2e` is `-0.78V`. Calculate the reduction in 9 molar `H^(+)` assuming all other species at unit concentration. What will be the reduction potential in neutral medium? |
|
Answer» Correct Answer - `0.836"volt", 1.1937"volt"` `E_("oxidation")=-0.78-(0.0591)/(2)log9^(2)=-0.78-(0.0591)/(2)xx2xxlog9=-0.835"volt"` `E_("reduction")=-E_("oxidation")=0.836"volt"` In neutral medium `E_("Oxidation")=-0.78-(0.0591)/(2)log(10^(-7))^(2)=-1.1937"volt"` |
|