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The straight line `x+y=0`, `3x+y-4=0`, `x+3y-4=0` form a triangle which isA. isosclesB. equilateralC. right angledD. None of the above

Answer» The points of intersection of three lines are `A(1,1)`, `B(2,-2)`, `C(-2,2)`.
Now, `|AB|=sqrt(1+9)=sqrt(10)`,
`|BC|=sqrt(16+16)=4sqrt(2)`,
and `|CA|=sqrt(9+1)=sqrt(10)`
`:.` Triangle is in isosceles.


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