InterviewSolution
 Saved Bookmarks
    				| 1. | 
                                    The straight line `x+y=0`, `3x+y-4=0`, `x+3y-4=0` form a triangle which isA. isosclesB. equilateralC. right angledD. None of the above | 
                            
| 
                                   
Answer» The points of intersection of three lines are `A(1,1)`, `B(2,-2)`, `C(-2,2)`. Now, `|AB|=sqrt(1+9)=sqrt(10)`, `|BC|=sqrt(16+16)=4sqrt(2)`, and `|CA|=sqrt(9+1)=sqrt(10)` `:.` Triangle is in isosceles.  | 
                            |