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The strings of a parachute can bear a maximum tension of `72 kg` wt . By what minimum acceleration can a person of 90 kg descend by means of this parachute ?

Answer» Here ` T = 72 kg wt . = 72 xx 9.8 N `
`m = 90 kg , a = ? ` for the person to descend ,
`T = (g-a)`
`72 xx 9.8 = (9.8-a ) (72xx9.8)/(90)=9.8-a 0.8 xx 9.8 = 9.8 - a`
`a = 9.8 - 0.8 xx 9.8 = 9.8 (1-0.8)= 1.96 m//s^(2) ` .


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