The sublimation energy of `I_(2)(s)` is 57.3 kJ `//` mol and the enthalpy of fusion is 15.5 kJ `//` mol. The enthalpy of vaporisation of `I_(2)` isA. 41.8 kJ `//` molB. `-41.8 kJ //` molC. 72.8 kJ`//` molD. `-72.8 kJ // `mol

The sublimation energy of `I_(2)(s)` is 57.3 kJ `//` mol and the entha

1.	The sublimation energy of `I_(2)(s)` is 57.3 kJ `//` mol and the enthalpy of fusion is 15.5 kJ `//` mol. The enthalpy of vaporisation of `I_(2)` isA. 41.8 kJ `//` molB. `-41.8 kJ //` molC. 72.8 kJ`//` molD. `-72.8 kJ // `mol
Answer» Correct Answer - a `DeltaH_("sub")= DeltaH_("fusion") + DeltaH _(vap)`

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The sublimation energy of `I_(2)(s)` is 57.3 kJ `//` mol and the enthalpy of fusion is 15.5 kJ `//` mol. The enthalpy of vaporisation of `I_(2)` isA. 41.8 kJ `//` molB. `-41.8 kJ //` molC. 72.8 kJ`//` molD. `-72.8 kJ // `mol

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