The sublimation energy of `I_(2)` (solid) is 57.3 KJ/mole and enthalpy of fusion is 15.5 KJ/mole. The enthalpy of vapourisation of `I_(2)` isA. 41.8 KJ/moleB. `-41.8 KJ//"mole"`C. `72.8 KJ//"mole"`D. `-72.8 KJ//"mole"`

The sublimation energy of `I_(2)` (solid) is 57.3 KJ/mole and enthalpy

1.	The sublimation energy of `I_(2)` (solid) is 57.3 KJ/mole and enthalpy of fusion is 15.5 KJ/mole. The enthalpy of vapourisation of `I_(2)` isA. 41.8 KJ/moleB. `-41.8 KJ//"mole"`C. `72.8 KJ//"mole"`D. `-72.8 KJ//"mole"`
Answer» Correct Answer - A `I_(2)(S) rarr I_(2)(l) rarr I_(2)(g)` `Delta H_(SE) = Delta H_("Fusion") + Delta H_("Eva")`

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The sublimation energy of `I_(2)` (solid) is 57.3 KJ/mole and enthalpy of fusion is 15.5 KJ/mole. The enthalpy of vapourisation of `I_(2)` isA. 41.8 KJ/moleB. `-41.8 KJ//"mole"`C. `72.8 KJ//"mole"`D. `-72.8 KJ//"mole"`

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