InterviewSolution
Saved Bookmarks
| 1. |
The sum of 10 terms of the series `sqrt2 + sqrt6 + sqrt18 +...` is |
|
Answer» Correct Answer - `121(sqrt(6)+sqrt(2))` Given series a geometric series in which `a =sqrt(2),r=sqrt(3) and n=10.` `therefore S=(a(r^(n)-1))/((r-1))=(sqrt(2){(sqrt(3))^(10)-1})/((sqrt(3)-1))xx((sqrt(3)+1))/((sqrt(3)+1))=(sqrt(2)(243-1)(sqrt(3)+1))/(2)` `rArr S=121(sqrt(6)+sqrt(2)).` |
|