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The sum of 10th and 16th term of an Arithmetic progression is 10 the comman difference is -9 Find it's 15th term . a15 = |
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Answer» ong>ANSWER: - 13 Explanation: Let the first term of the AP is a Then, A/Q, a + 9×(-9) + a + 15×(-9) = 10 Or, 2a - 81 - 135 = 10 Or, 2a = 10 + 81 + 135 Or, 2a = 226 Or, a = 226/2 Or, a = 113 Therefore the 15th term of AP is a + 14D = 113 + 14×(-9) = 113 - 126 = - 13 Ans. |
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