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The sum of two numbers is \(\frac{-4}{7}\) to get \(\frac{5}{6}\,?\)A. \(\frac{5}{2}\)B. \(\frac{3}{2}\)C. \(\frac{5}{4}\)D. \(\frac{-5}{2}\) |
Answer» Let the number added be x. Then, \(\frac{5}{6}+\text{x}=\frac{-4}{7}\) \(\Rightarrow\) \(\text{x}=\frac{-4}{7}-\frac{5}{6}\) \(=\frac{-4\times6-5\times7}{42}\) \(=\frac{-24-35}{42}\) \(=\frac{-59}{42}\) |
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