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The surface tension for pure water in a capillary tube experiment isA. `(pg)/(2hr)`B. `(2)/(hrpg)`C. `(rpg)/(2h)`D. `(hrpg)/(2)` |
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Answer» Correct Answer - D Surface tension, `S = (rh rho g)/(2 cos theta)` `= (rh rho g)/(2 cos 0^(@))` (`because` for pure water `theta = 0^(@)`) `= (rh rho g)/(2)` |
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