1.

The switch in the circuit shown was on position X for a long time. The switch is then moved to position Y at time t=0. The current I(t) for t>0 is ________(a) 0.2e^-125tu(t) mA(b) 20e^-1250tu(t) mA(c) 0.2e^-1250tu(t) mA(d) 20e^-1000tu(t) mAThis question was posed to me in a job interview.This interesting question is from Dot Convention in Magnetically Coupled Circuits in section Resonance & Magnetically Coupled Circuit of Network Theory

Answer»

The correct choice is (C) 0.2e^-1250tu(t) mA

The BEST explanation: CEQ = \(\frac{0.8 × 0.2}{0.8+0.2}\) = 0.16

VC (t=0^–) = 100 V

At t≥0,

The discharging current I (t) = \(\frac{V_O}{R} E^{-\frac{t}{RC}}\)

= \(\frac{100}{5000} e^{- \frac{t}{5×10^3×0.16×10^{-6}}}\)

= 0.2e^-1250tu(t) mA.



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