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The symmetric difference of A = {1, 2, 3} and B = {3, 4, 5} is A. {1, 2} B. {1, 2, 4, 5} C. {4, 3} D. {2, 5, 1, 4, 3} |
Answer» Here, A = {1,2,3} and B = {3,4,5} A∖B={1,2,3}∖{3,4,5} ={1,2,3}∖{3} ={1,2} B∖A = {3,4,5}∖{1,2,3,4} = {3,4,5}∖{3} = {4,5} AΔB = (A∖B)⋃(B∖A) = {1,2}⋃{4,5} = {1,2,4,5} |
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