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The temperature at which the average speed of perfect gas molecules is double than at `17^(@)C` isA. `34^(@)C`B. `68^(@)C`C. `162^(@)C`D. `887^(@)C` |
Answer» Correct Answer - D Average speed `(V_(av)) prop (T)^(1/2)` `:. (V_(av))_(2)/(V_(av))_(1) = sqrt((T_(2))/(T_(1)))` `("Given" ((V_(av))_(2))/(V_(av))_(1) = 2)` `(2)^(2) = (T_(2))/(T_(1)) rArr T_(2) = 4T_(1)` `T_(1) = 273 + 17 = 290 K` `:. T_(2) = 4 xx 290 = 1160 K = 1160 - 273 = 887^(@)C` |
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