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The temperature at which the velocity of sound in oxygen will be same as that of nitrogen at `15^(@) C` isA. `112^(@) C`B. `72^(@) C`C. `56^(@) C`D. `17 ^(@) C` |
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Answer» Correct Answer - C `nu = sqrt((gammaRT) /(M)) prop sqrt((T) / (M))` `(gamma = 1.4` for both) :. `T_(o_2)/M_(o_2) = T_(N_2)/M_(N_2)` :. `T_(o_2) = ((M_(o_2))/(M_(N_2))) T_(N_2)` = `((32) /(28)) (273 + 15)` = `329 K = 56^(@) C` |
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