The temperature of a gas contained in a closed vessel increases by 1'C

1.	The temperature of a gas contained in a closed vessel increases by 1'C when paessure of theincreased by 1%. The initial temperature of the gas isgasi250 K(d) 250 C
Answer» Let P2 = 1.004 P1 ..... A 0.4% increase in PLet T2 = T1 + 1 ........... See note below P1V1/T1 = P2V2/T2 ..... combined gas lawP1/T1 = P2/T2 ............... Assume V remains constant.T1 = P1T2 / P2 .............. solve for T1T1 = P1(T1+1) / (1.004P1)T1 = (T1+1) / 1.0041.004T1 = T1 + 11.004T1 - T1 = 10.004T1 = 1T1 = 1 / 0.004T1 = 250K Note: A 1 degree increase on the Celsius scale is a 1 degree increase on the Kelvin scale. Temperatures used in the combined gas law must be in Kelvin. how P2=0.004

The temperature of a gas contained in a closed vessel increases by 1'C when paessure of theincreased by 1%. The initial temperature of the gas isgasi250 K(d) 250 C

Answer»

Let P2 = 1.004 P1 ..... A 0.4% increase in PLet T2 = T1 + 1 ........... See note below

P1V1/T1 = P2V2/T2 ..... combined gas lawP1/T1 = P2/T2 ............... Assume V remains constant.T1 = P1T2 / P2 .............. solve for T1T1 = P1(T1+1) / (1.004P1)T1 = (T1+1) / 1.0041.004T1 = T1 + 11.004T1 - T1 = 10.004T1 = 1T1 = 1 / 0.004T1 = 250K

Note: A 1 degree increase on the Celsius scale is a 1 degree increase on the Kelvin scale. Temperatures used in the combined gas law must be in Kelvin.

how P2=0.004

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