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The tension of a stretched string is increased by 69%. In order to keep its frequency of vibration constant, its length must be increased by :A. 0.2B. 0.3C. `sqrt(69)%`D. 0.69 |
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Answer» Correct Answer - B `l_1/l_2 = sqrt(T_2/T_1) = sqrt(169/100) = 13/10` `l_1/l_2 = 1.3` `(l_1-l_2)/(l_2) = 1.3 - 1 0.3` `(Deltal)/(l) = 30%` |
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