The thermal efficiency of a heat engine is 25%. If in one cycle the he

1.	The thermal efficiency of a heat engine is 25%. If in one cycle the heat absorbed from the hot reservoir is 50000 J, what is the heat rejected to the cold reservoir in one cycle ?
Answer» Data : η = 25% = 0.25, Q_H = 50000 J W η = \(\frac{W}{Q_H}\) ∴ W = _ηQ_H = (0.25)(50000)J = 12500J Now, W = Q_H – \|Q_C\| ∴ \|Q_C\| = Q_H – W = (50000 – 12500) J = 37500J This is the heat rejected to the cold reservoir in one cycle. [Notes : Q_C = – 37500 J]

The thermal efficiency of a heat engine is 25%. If in one cycle the heat absorbed from the hot reservoir is 50000 J, what is the heat rejected to the cold reservoir in one cycle ?

Answer»

Data : η = 25% = 0.25, Q_H = 50000 J W

η = \(\frac{W}{Q_H}\)

∴ W = _ηQ_H = (0.25)(50000)J = 12500J

Now, W = Q_H – |Q_C|

∴ |Q_C| = Q_H – W

= (50000

– 12500) J = 37500J

This is the heat rejected to the cold reservoir in one cycle.

[Notes : Q_C = – 37500 J]

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The thermal efficiency of a heat engine is 25%. If in one cycle the heat absorbed from the hot reservoir is 50000 J, what is the heat rejected to the cold reservoir in one cycle ?

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