InterviewSolution
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The three blocks shown move with constant velocities. Find the velocity of block A and B2应直 |
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Answer» (Va + Vp2)/2 = Vp1 ( that is 0) => Va = -Vp2 = -10m/s ↑ now (Vb + Vc)/2 = Vp2=> Vb = 2(Vp2) - Vc = 2*(10) -2 = 18 m/s ↑ |
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