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The time for half life period of a certain reaction `A to` Products A is `2.0 mol L^(-1)`, how much time does it take for its concentration to come from `0.50` to `0.25` mol `L^(-1)` if it is a zero order reaction?A. 1 hB. 4 hC. `0.5`hD. `0.25`h |
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Answer» Correct Answer - D d) For zero order of reaction. `t_(1//2) = ([A_(0)])/(2k)` or `k=([A_(0)])/(2t_(1//2))` `k=(2.0molL^(-1))/(2 xx 1hr)=1 molL^(-1)hr^(-1)` For zero order reaction, `t=([A]_(0)-[A])/(k)` `((0.5-0.2s)mol L^(-1))/(1 mol L^(-1) hr^(-1))` = 0.25 hr. |
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